Problem:1
psudo code:
- Take the length of rectangle from user.
- Take the width of rectangle from user.
- Find the area of rectangle by this formula: area=length*width
- find the perimeter of rectangle using this formula: perimeter=2*(length+width)
program of problem 1
#include “stdafx.h”
#include “iostream”
#include “conio.h”
using namespace std;
int main()
{
float width,length,peri,area;
printf(“Enter the length of rectangle:”);
scanf(“%f”,&length);
printf(“Enter the width of rectangle:”);
scanf(“%f”,&width);
area=length*width;
printf(“The area of rectangle is:%f”);
peri=2*(length+width);
printf(“the perimeter of rectangle is:%f”);
getch();
return 0;
}
Problem 2
psudo code
- Take the salaries of eight employees as a input from the user one by one.
- Calculate the average salary of employees by average=sum of salaries of eight employees/8
program of problem 2
#include “stdafx.h”
#include “iostream”
#include “conio.h”
using namespace std;
int main()
{
int s1,s2,s3,s4,s5,s6,s7,s8;
float avg;
printf(“enter the salaries of eight of employees one by one”);
scanf(“%d%d%d%d%d%d%d%d”,&s1,&s2,&s3,&s4,&s5,&s6,&s7,&s8);
avg=(s1+s2+s3+s4+s5+s6+s7+s8)/8;
printf(“%d”,avg);
getch();
return 0;
}
Problem 3
psudo code
- Take the temperature of any place in Fahrenheit from the user.
- Convert the temperature into centigrade using C = (F-32)*5/9.
- Show the temperature in centigrade o n the screen
Program of Problem 3
#include “stdafx.h”
#include “iostream”
#include “conio.h”
using namespace std;
int main()
{
float c,f;
printf(“Enter the temperature in fahrenheit:”);
scanf(“%d”,&f);
c=(f-32)*5/9;
printf(“%f”,c);
return 0;
}
Problem no. 4
PSUDO CODE
- Take a any number from the user
- Use modulus operator of user number with 2
- If reminder is 0 then print “the number is even”
- Else print “the number is odd”
Program no. 4
#include “stdafx.h”
#include “iostream”
#include “conio.h”
int main()
{
int n;
printf(“Enter any number:”);
scanf(“%d”,&n);
if(n%2==0)
printf(“the number is even”);
else
printf(“the number is odd”);
getch();
return 0;
}
PROBLEM # 5
PSUDO CODE
- Take a 4 digit number from the user
- And number is divided by 1000 like (a=n/1000 )
- Take the modulus of n with 1000 (n=n%1000 )
- the answer of modulus is divided by 100 (b=n/100 )
- Again take modulus of the answer of first modulus (n%100 )
- Again the answer is divide by 100
- Again the modulus of second answer of second modulus
- And the answer is divide by 10
- Then arrange the values in from ending to start
Flow Chart
PROGRAM> 5
#include “stdafx.h”
#include “iostream”
#include “conio.h”
using namespace std;
int main()
{
int n,a,b,c;
printf(” Enter a 4 digit number:”);
scanf(“%d”,&n);
a=n/1000;
n=n%1000;
b=n/100;
n=n%100;
c=n/10;
n=n%10;
printf(“%d%d%d%d”,n,c,b,a);
getch();
return 0;
}
PROBLEM NO.6
PSUDO CODE
- Take two numbers a=21 and b=12
- Consider third variable lets c
- Assign the value of a to c then b to a and c to a
- Then print numbers..the values must be swaps
FLOW CHART
PROGRAM> 6
#include “stdafx.h”
#include “iostream”
#include “conio.h”
using namespace std;
int main()
{
int a=21,b=12,c;
printf(“the values of a and b is 21 and 12 before swaping”);
c=a;
a=b;
b=c;
printf(“the values of a and b is %d and %d after swaping”,a,b);
getch();
return 0;
}
PROBLEM no.7
PSUDO CODE
- Take the hours, minutes and seconds by user one by one
- Then we calculate the total seconds using this formula: sec_in_hours=hour*min/hour*sec/min
- Then print the total seconds into the secreen
PROGRAM >> 7
#include “stdafx.h”
#include “iostream”
#include “conio.h”
using namespace std;
int main()
{
int hours,mins,secs,sec_in_hours;
printf(“Enter the hours:”);
scanf(“%d”,&hours);
printf(“Enter the minutes:”);
scanf(“%d”,&mins);
printf(“Enter the seconds:”);
scanf(“%d”,&secs);
sec_in_hours=hours*mins/hours*secs/mins;
printf(“%d”,sec_in_hours);
getch();
return 0;
}
PROBLEM no.8
PSUDO CODE
- Take the value of radius from the user
- Put in the equation : diameter=2*radius
- Print the diameter
PROGRAM>>8
// pro8.cpp : to find the diameter of the circle.
//
#include “stdafx.h”
#include “iostream”
#include “conio.h”
using namespace std;
int main()
{
int d,r;
printf(“enter the radius of the circle:”);
scanf(“%d”,&r);
d=2*r;
printf(“%d”,d);
getch();
return 0;
}
PROBLEM no.9
PSUDO CODE
- In this problem we use for loop of 10 cycles
- Take a number from the user for any cycle
- If n%2!=0
- Then sum=sum+1
- This process is continuous for 10 readings
- If any odd number is add by user then sum the number otherwise not
- Then print the sum of odd numbers
PROGRAM>>9
// pro 9.cpp : Addition of odd numbers.
//
#include “stdafx.h”
#include “iostream”
#include “conio.h”
using namespace std;
int main()
{
int i,n,sum;
sum=0;
for(i=1;i<=10;i++)
{
printf(“Enter a number:”);
scanf(“%d”,&n);
if(n%2==1)
sum=sum+n;
}
printf(“%d”,sum);
getch();
return 0;
}
Problem no.10
PSUDO CODE
- Take a number from the user
- Using this equation: cube=num*num*num
- Then print the cube
- The output will be shown on the screen
PROGRAM>>10
// pro 10.cpp : Take a cube of number.
//
#include “stdafx.h”
#include “iostream”
#include “conio.h”
using namespace std;
int main()
{
int num=0,cube=0;
printf(“Enter a number:”);
scanf(“%d”,num);
cube=num*num*num;
printf(“%d”,cube);
getch();
return 0;
}
the end